A new report being released today by the Census Bureau finds that Manhattan has the highest level of income inequality in the United States. That is not entirely surprising, though it would also not have been surprising if it had been San Francisco or another progressive fiefdom. For all the rhetoric about wicked 1 percenters and inequality, progressivism is a luxury good, and progressive-dominated enclaves are generally pretty okay places to live if you have a fair amount of money, but sort of stink if you’re in the middle or at the lower end of the earnings curve.
Because most Americans experience New York City as tourists or in television shows and movies, it is easy to forget that the hometown of Wall Street and a very large population of obnoxious celebrities is a poor city: New York City is not only poorer than the New York State average, its median household income is, in absolute dollar terms, lower than that of such dramatically less expensive areas as Austin, Texas, or Cleveland County, Okla., where the typical household income is a few thousand dollars a year more than in New York City but the typical house costs less than a third of what the typical New York City home costs — and 17 percent of what the average Manhattan home costs. (And it’s a house, not a two-room coop.)